2026-09-19 11:02 UTC
FILENAME='birthday_0' $(cat command_ffmpeg_SYNCAUD)
cat prints out a file without altering it’s contents.
If it’s important to keep the commands in a separate file, you could use sed to find/replace, or use eval, or use some external template engine (lookup “bash expand variables in file”).
What you probably want to do instead, I assume, is to replace the external files with regular bash variables:
filename="some-file"
command="ffmpg -i ${filename}.mpg -bla -blabla ${filename}.mkv"
echo "$command"
Replies (1)
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@akunohana@piefed.blahaj.zone 2026-09-19 11:07
Thanks! “Solving” it with bash does seem to be the easiest way forward. I’ll fiddle around with it some! :D