2026-09-13 02:04 UTC
@bobjonkman@mastodon.sdf.org @jpaskaruk@growers.social I might not understand the original data correctly.
But I’ll often do something like the following:
sed -n ‘/-A/,/^$/p’
Print lines that contain ‘-A’ through blank lines.
Replies (1)
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@gumnos@mastodon.bsd.cafe 2026-09-13 02:12
Seconding @drscriptt@oldbytes.space's suggestion here. But running with @bobjonkman@mastodon.sdf.org's, the #awk syntax would be similar: awk '/-A/,/^$/' or awk '/-A/,!length' @jpaskaruk@growers.social